A simple pendulum consists of a concentrated mass known as the ‘bob’, which is free to swing from side to side at the end of a light cord or rod. When bob is given a small angular displacement and released, the pendulum bob appears to describe simple harmonic motion (SHM). It doesn’t travel along a perfectly straight line, but for small angular displacements it is approximately straight, with a central equilibrium position.

If the mass is given a small displacement (*r*) from its equilibrium position and then released, it will oscillate about the equilibrium position with amplitude ‘r’ as shown in figure 1 (a). At some instant when the bob is at distance ‘x’ from its equilibrium position, and accelerating towards it, the forces acting on it will be as shown in figure 1 (b). It is assumed that the bob oscillates with *free* or *natural vibrations*, i.e. that the air resistance is negligible and that there are no energy losses at the point of suspension.

Equating forces in the direction of motion at the instant shown gives:

ma = mg sin θ

a = g sin θ

But

Acceleration of the system is also given by the general formula:

The natural circular frequency of the system ω rad s^{-1} is thus given by the formula:

The periodic time of the natural vibrations is given by the formula:

The natural frequency of the vibrations is the reciprocal of periodic time is given by the formula:

In the mass-spring systems there is always some air resistance.

There is also some energy losses at the point of suspension in the simple pendulum and the combined effect would cause the vibrations to die away.